프로그래머스 | 즐겨찾기가 가장 많은 식당 정보 출력하기

SELECT FOOD_TYPE, REST_ID, REST_NAME, FAVORITES FROM REST_INFO
WHERE FOOD_TYPE IN (SELECT FOOD_TYPE FROM REST_INFO
                    GROUP BY FOOD_TYPE HAVING FAVORITES = MAX(FAVORITES))
ORDER BY FOOD_TYPE DESC;